New Step by Step Map For pnl

That isn't the same as the pnl equalling the price paid, instead the envisioned pnl in the method will be the same as the choice value. $endgroup$Kurt G.Kurt G. two,38944 silver badges1717 bronze badges $endgroup$ three $begingroup$ Many thanks a good deal for taking the time to answer. As a result of your very last equality I know that the "univer

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